Factorise:

$x (x - 2) (x - 4) + 4 x - 8$

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Solution

$x (x - 2) (x - 4) + 4 x - 8 = x (x - 2) (x - 4) + 4 (x - 2) = (x - 2) [x (x - 4) + 4] = (x - 2) (x^{2} - 4 x + 4) = (x - 2) [(x)^{2} - 2 \times x \times 2 + (2)^{2}] = (x - 2) (x - 2)^{2} = (x - 2)^{3}$

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Similar questions

\frac{2 x - 3}{4} + 8 \geq 2 + \frac{4 x}{3}

Factorise:
$x (x + y)^{3} - 3 x^{2} y (x + y)$

\frac{2 x - 3}{4} + 8 \geq 2 + \frac{4 x}{3}

\frac{2 x - 3}{4} + 8 \geq 2 + \frac{4 x}{3}

(2 x^{2} + 4 x + 8) - (2 x^{2} - 4 x + 7)

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