Factorise : $y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x$

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Solution

Given that: $y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x$
$= (y^{3} - 3 y^{2}) + (2 y - 6) + (- x y + 3 x)$ , (group pair of terms)
$= y^{2} (y - 3) + 2 (y - 3) - x (y - 3)$ , (factor each binomials)
$= (y - 3) (y^{2} + 2 - x)$ , (factor out common factor $(y - 3)$ )
The common factors of $y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x$ are $(y - 3) (y^{2} + 2 - x)$

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Similar questions

y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x

Factorise:

(i) ; (ii) ; (iii) ;

(iv)

Factorize:

$y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x$

x^{2} + x y - 3 x - 3 y

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