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Question
Get the factors of y3−3y2+2y−6−xy+3x
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Solution
Here we group the terms in the expression and factorize:
y3−3y2+2y−6−xy+3x=(y3−3y2)+(2y−6)−(xy−3x)
=y2(y−3)+2(y−3)−x(y−3)=(y2+2−x)(y−3).
y3−3y2+2y−6−xy+3x=(y3−3y2)+(2y−6)−(xy−3x)
=y2(y−3)+2(y−3)−x(y−3)=(y2+2−x)(y−3).
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