Factorised form of 23xy – 46x + 54y – 108 is
(a) (23x + 54) (y – 2)
(b) (23x + 54y) (y – 2)
(c) (23xy + 54y) (– 46x – 108)
(d) (23x + 54) (y + 2)

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Solution

Factorise the given expression:
The given expression is
$23 x y - 46 x + 54 y - 108 = 23 x y + 54 y - 46 x - 108 = y (23 x + 54) - 2 (23 x + 54)$
Take $(23 x + 54)$ common
$= (23 x + 54) (y - 2)$
Hence Option (A) is correct

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23 x y - 46 x + 54 y - 108

(23 x + 54) (y - 2)

(23 x + 54 y) (y - 2)

(23 x y + 54 y) (- 46 x - 108)

(23 x + 54) (y + 2)

23 x y - 46 x + 54 y - 108

(23 x + 54) (y - 2)

(23 x + 54 y) (y - 2)

(23 x y + 54 y) (- 46 x - 108)

(23 x + 54) (y + 2)

x^{2} - 23 x + 108

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