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Question

Factorize: 121b2+88bc+16c2

A
(11b4c)2
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B
(4b+11c)2
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C
(4b11c)2
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D
(11b+4c)2
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Solution

The correct option is D (11b+4c)2
121b2+88bc+16c2
=(11b)2+2×11b×4c+(4c)2
=(11b+4c)2

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