Factorize $12 x^{2} + 36 a^{2} = 43 a x$

(4 x - 9 a) (3 x - 4 a)

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(4 x - 3 a) (x - 4 a)

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(2 x - 5 a) (3 x - 4 a)

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Solution

The correct option is A $(4 x - 9 a) (3 x - 4 a)$
$12 x^{2} + 36 a^{2} = 43 a x$
$\Rightarrow 12 x^{2} - 43 a x + 36 a^{2} = 0$
$\Rightarrow 12 x^{2} - 27 a x - 16 a x + 36 a^{2} = 0$
$\Rightarrow 3 x (4 x - 9 a) - 4 a [4 x - 9 a] = 0$
$\Rightarrow (3 x - 4 a) (4 x - 9 a)$

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