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Byju's Answer
Standard VIII
Mathematics
Factorisation Using Algebraic Identities
Factorize 25...
Question
Factorize
25
x
2
+
16
y
2
+
4
z
2
−
40
x
y
+
16
y
z
−
20
x
z
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Solution
25
x
2
+
16
y
2
+
4
z
2
−
40
x
y
+
16
y
z
−
20
x
z
=
(
−
5
x
)
2
+
(
4
y
)
2
+
(
2
z
)
2
+
2
(
−
5
x
)
(
4
y
)
+
2
(
4
y
)
(
2
z
)
+
2
(
−
5
x
)
(
2
z
)
Suitable identities is
(
x
+
y
+
z
)
2
=
x
2
+
y
2
+
z
2
+
2
x
y
+
2
y
z
+
2
x
z
Therefore,
(
−
5
x
)
2
+
(
4
y
)
2
+
(
2
z
)
2
+
2
(
−
5
x
)
(
4
y
)
+
2
(
4
y
)
(
2
z
)
+
2
(
−
5
x
)
(
2
z
)
=
(
−
5
x
+
4
y
+
2
z
)
2
Suggest Corrections
2
Similar questions
Q.
Factorise the following:
25
x
2
+
16
y
2
+
4
z
2
+
40
x
y
+
16
y
z
+
20
x
z
Q.
Question 29
Factorise the following:
(i)
9
x
2
+
4
y
2
+
16
z
2
+
12
x
y
–
16
y
z
–
24
x
z
(ii)
25
x
2
+
16
y
2
+
4
z
2
–
40
x
y
+
16
y
z
–
20
x
z
(iii)
16
x
2
+
4
y
2
+
9
z
2
–
16
x
y
–
12
y
z
+
24
x
z
Q.
Question 29
Factorise the following:
(i)
9
x
2
+
4
y
2
+
16
z
2
+
12
x
y
–
16
y
z
–
24
x
z
(ii)
25
x
2
+
16
y
2
+
4
z
2
–
40
x
y
+
16
y
z
–
20
x
z
(iii)
16
x
2
+
4
y
2
+
9
z
2
–
16
x
y
–
12
y
z
+
24
x
z
Q.
Factorize 16x²–16y²–16yz–4z²
Q.
The value of
25
x
2
+
16
y
2
+
40
x
y
at
x
=
1
and
y
=
−
1
is
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