Question

Factorize:
(3a − 1)² − 6a + 2

Answer 1

We have:
${\left(3a-1\right)}^2-6a+2={\left(3a-1\right)}^2-2\left(3a-1\right)$
$$\begin{gathered} =\left(3a-1\right)\left[\left(3a-1\right)-2\right] \\ =\left(3a-1\right)\left(3a-1-2\right) \\ =\left(3a-1\right)\left(3a-3\right) \\ =3\left(3a-1\right)\left(a-1\right) \end{gathered}$$