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Question

Factorize 3a2−9ab by taking common factors.

A
3a(a3b)
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B
3a(ab)
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C
3a(3ab)
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D
3a(a+b)
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Solution

The correct option is C 3a(a3b)
3a29ab
3 and a are common in the above two terms in the addition, so taking these as common.
3a29ab=3a(a3b)
Option A is correct.

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