Factorize- 48 a 2-24-1-48 a2A- 62 a -1-2 a 2B- 43 a -1-3 a 2C- 122 a -1-222D- 43 a -1-3 a 2

The correct option is C 12(2a + 1/2a)^2⇒ 48a^2 + 24 + 12/4a^2 ⇒ 12[4a^2 + 2 + 1/4a^2] ⇒ 12[(2a)^2 + 2(2a) (1/2a) + 1/(2a)^2] ⇒ 12[(2a)^2 + 2a/2a + 2a/2a + 1 ...

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Byju's Answer

Standard IX

Mathematics

Perfect Square Trinomials

Factorize: 48...

Question

Factorize: $48 a^{2} + 24 + \frac{1}{48 a^{2}}$

6 (2 a + \frac{1}{2 a})^{2}

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12 (2 a + \frac{1}{2 a})^{2}

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4 (3 a + \frac{1}{3 a})^{2}

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4 (3 a + \frac{1}{3 a})^{2}

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Solution

The correct option is B $12 (2 a + \frac{1}{2 a})^{2}$
$\Rightarrow 48 a^{2} + 24 + \frac{12}{4 a^{2}}$

$\Rightarrow 12 [4 a^{2} + 2 + \frac{1}{4 a^{2}}]$

$\Rightarrow 12 [(2 a)^{2} + 2 (2 a) (\frac{1}{2 a}) + \frac{1}{(2 a)^{2}}]$

$\Rightarrow 12 [(2 a)^{2} + \frac{2 a}{2 a} + \frac{2 a}{2 a} + \frac{1}{(2 a)^{2}}]$

$\Rightarrow 12 [2 a (2 a + \frac{1}{2 a}) + \frac{1}{2 a} (2 a + \frac{1}{2 a})]$

$\Rightarrow 12 (2 a + \frac{1}{2 a}) (2 a + \frac{1}{2 a})$

$\Rightarrow 12 (2 a + \frac{1}{2 a})^{2}$

Suggest Corrections

Factorize: 48a2+24+148a2

The correct option is B 12(2a+12a)2⇒48a2+24+124a2 ⇒12[4a2+2+14a2] ⇒12[(2a)2+2(2a)(12a)+1(2a)2] ⇒12[(2a)2+2a2a+2a2a+1(2a)2] ⇒12[2a(2a+12a)+12a(2a+12a)] ⇒12(2a+12a)(2a+12a) ⇒12(2a+12a)2

Factorize: $48 a^{2} + 24 + \frac{1}{48 a^{2}}$