Factorize the below equation:
$3 a^{2} - 1 - 2 a$

(2 a - 1) (3 a - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a - 1) (3 a + 1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2 a - 1) (a + 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + 1) (2 a + 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(a - 1) (3 a + 1)$
$3 a^{2} - 1 - 2 a$
$= 3 a^{2} - 2 a - 1$
$= 3 a^{2} - 3 a + a - 1$
$= 3 a (a - 1) + 1 (a - 1)$
$= (a - 1) (3 a + 1)$

Suggest Corrections

Similar questions

3 a^{2} - 1 - 2 a

5 - (3 a^{2} - 2 a) (6 - 3 a^{2} + 2 a)

$6 a^{2} - 13 a + 6 = ? (a) (2 a + 3) (3 a - 2) (b) (2 a - 3) (3 a + 2) (c) (3 a - 2) (2 a - 3) (d) (3 a + 1) (2 a - 3)$

1 - 2 a - 3 a^{2}

(2 a + b)^{2} - 6 a - 3 b - 4

Join BYJU'S Learning Program