Factorize:
$4 a^{2} - 12 a + 9 - 49 b^{2}$

(2 a + 7 b - 3) (8 a - 7 b - 3)

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(2 a - 7 b - 3) (8 a - 7 b + 3)

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(2 a - 7 b - 3) (2 a - 7 b + 3)

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(2 a + 7 b - 3) (2 a - 7 b - 3)

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Solution

The correct option is C $(2 a + 7 b - 3) (2 a - 7 b - 3)$
Given, $4 a^{2} - 12 a + 9 - 49 b^{2}$
$= (2 a)^{2} - 2 (2 a) (3) + 3^{2} - (7 b)^{2}$
$= (2 a - 3)^{2} - (7 b)^{2}$
Now by using $a^{2} - b^{2} = (a + b) (a - b)$
$= (2 a - 3 + 7 b) (2 a - 3 - 7 b)$

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Similar questions

4 a^{2} - 49 b^{2} + 2 a - 7 b

Factorise:

$4 a^{2} - 49 b^{2} + 2 a - 7 b$

If a : b = 5 : 3, find (2a + 7b) : (6a - 7b).

Factorize 98 $(a + b)^{2} - 2$

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