Factorize:
$6 (2 a + 3 b)^{2} - 8 (2 a + 3 b)$

Open in App

Solution

$6 (2 a + 3 b)^{2} - 8 (2 a + 3 b)$
=Take out (2a+3b)common,
(2a+3b)[6(2a+3b)-8]
=2(2a+3b)[3(2a+3b)-4]
=2(2a+3b)[6a+9b-4]
=2(2a+3b)(6a+9b-4)

Suggest Corrections

Similar questions

8 (2 a + 3 b)^{3} - 12 (2 a + 3 b)^{2}

4 (2 a + 3 b)^{2} (4 a + 6 b - 3)

16 {(4 a - 3 b)}^{2} + 4 (4 a - 3 b)

2 a + 6 b - 3 (a + 3 b)^{2}

2 a + 6 b - 3 (a + 3 b)^{2}

= 2 (a + 3 b) - 3 (a + 3 b)^{2} [T a k i n g 2 c o m m o n f r o m 2 a + 6 b]

= (a + 3 b) {\begin{matrix} 2 - 3 (a + 3 b) \end{matrix}} [T a k i n g (a + 3 b) c o m m o n]

= (a + 3 b) (2 - 3 a - 9 b)

(a - 3 b)^{2} - 4 (a - 3 b) - 21

(2 a + 3 b)^{2} - 5 (2 a + 3 b) - 14

Join BYJU'S Learning Program