Factorize-6 a b-b2-12 a c-2 b c

The given expression to be factorized is Take common nbsp;b nbsp;from the first two terms and nbsp; nbsp;from the last two terms. That is Finally, ...

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Standard IX

Mathematics

Polynomials

Factorize:6 a...

Question

Factorize:

6ab − b² + 12ac − 2bc

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Solution

The given expression to be factorized is

Take common b from the first two terms and from the last two terms. That is

Finally, take commonfrom the two terms. That is

We cannot further factorize the expression.

So, the required factorization of is.

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Similar questions

Q. Factorise

6 a b - b^{2} - 2 b c + 12 a c

\frac{6 a b - b^{2} + 12 a c - 2 b c}{b + 2 c}

Divide (6 a b - b^{2} + 12 a c - 2 b c) by (b + 2 c)

(6 a b - b^{2} + 12 a c - 2 b c) d i v i d e d b y (6 a - b)

gives .

The quotient when $6 a b - b^{2} + 12 a c - 2 b c$ is divided by $(6 a - b)$ is ___

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Factorize: 6ab − b2 + 12ac − 2bc

The given expression to be factorized is Take common b from the first two terms and from the last two terms. That is Finally, take commonfrom the two terms. That is We cannot further factorize the expression. So, the required factorization of is.

Factorize:

6ab − b² + 12ac − 2bc

The given expression to be factorized is

Take common b from the first two terms and from the last two terms. That is

Finally, take commonfrom the two terms. That is

We cannot further factorize the expression.

So, the required factorization of is.