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Question

Factorize: a2+1a2−2−3a+3a

A
(a6a)(a1a1)
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B
(a3a)(a1a9)
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C
(a2a)(a1a7)
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D
(a1a)(a1a3)
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Solution

The correct option is D (a1a)(a1a3)
Given, a2+1a223a+3a
=a2+1a22(a)(1a)3(a1a)

=(a1a)23(a1a)

=(a1a)(a1a3)

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