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Question

Factorize :
a4−343a.

A
a(a7)(a3+a+36)
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B
a(a7)(a2+7a+49)
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C
a(4a7)(a2a+49)
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D
a(4a7)(a3+7a36)
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Solution

The correct option is B a(a7)(a2+7a+49)
a4343a
=a(a3343)
Using,
a3b3=(ab)(a2+b2+ab)
=a(a373)
=a(a7)(a2+72+7a)
=a(a7)(a2+49+7a)

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