Factorize:

$a^{4} - 5 a^{2} - 36$

$(a - 3) (a + 3) (a + 2) (a - 2)$

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$(a - 9) (a + 4)$

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$(a - 3) (a + 3) (a^{2} + 4)$

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$(a^{2} + 9) (a^{2} + 4)$

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Solution

The correct option is C
$(a - 3) (a + 3) (a^{2} + 4)$

$\Rightarrow a^{4} - 5 a^{2} - 36$

Taking $a^{2} = x$

$\Rightarrow x^{2} - 5 x - 36$

$\Rightarrow x^{2} - 9 x + 4 x - 36$

$\Rightarrow x (x - 9) + 4 (x - 9)$

$\Rightarrow (x - 9) (x + 4)$

$\Rightarrow (a^{2} - 9) (a^{2} + 4)$

$\Rightarrow (a - 3) (a + 3) (a^{2} + 4)$

Suggest Corrections

Similar questions

\frac{a^{2} - 16}{a^{3} - 8} \times \frac{2 a^{2} - 3 a - 2}{2 a^{2} + 9 a + 4} \div \frac{3 a^{2} - 11 a - 4}{a^{2} + 2 a + 4}

- 5 a^{2} - 2 a + 1

4 a^{2} + 3 - 7 a

8 a - 7

$3 a - [4 a - ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 3 a - 5 b - 3$ { $2 a - (3 a - ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 2 a - 3 b)$ } $]$ equals

3 a^{2} (2 a^{2} - 3) + 4 a (4 a^{3} + 3) - 12 (a + 1)

= 14 a^{4} - 9 a^{2} - 12

Evaluate : $(3 a - \frac{1}{2}) (3 a - \frac{1}{2})$

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