Factorize :
$a - b - 4 a^{2} + 4 b^{2}$

(b) (1 - a - 4 b)

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(a - b) (1 - 4 a - b)

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(b - a) (4 a - 4 b)

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(a - b) (1 - 4 a - 4 b)

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Solution

The correct option is D $(a - b) (1 - 4 a - 4 b)$
$a - b - 4 a^{2} + 4 b^{2}$
$= a - b - 4 (a^{2} - b^{2})$
$= a - b - 4 (a + b) (a - b)$
$= (a - b) (1 - 4 a - 4 b)$

Suggest Corrections

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16 {(a + b)}^{2} - 4 a - 4 b

2 (a x - b y) + (a + 4 b) = 0, 2 (b x + a y) + (b - 4 a) = 0 .

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