Factorize by the grouping method :
$a^{3} + a - 3 a^{2} - 3$

(a^{2} + 1) (a - 3)

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(a^{2} - 1) (a - 3)

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(a^{2} + 1) (a + 3)

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(a^{2} - 1) (a + 3)

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Solution

The correct option is A $(a^{2} + 1) (a - 3)$
$a^{3} + a - 3 a^{2} - 3$
$= a (a^{2} + 1) - 3 (a^{2} + 1)$
$= (a^{2} + 1) (a - 3)$

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Similar questions

a^{3} + a - 3 a^{2} - 3

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{sin}^{- 1} (a - \frac{a^{2}}{3} + \frac{a^{3}}{9} + . . .) + {cos}^{- 1} (1 + b + b^{2} + . . .) = \frac{π}{2}

s i n^{- 1} (a - \frac{a^{2}}{3} + \frac{a^{3}}{9} - . . . . . . \infty) + c o s^{- 1} (1 + b + b^{2} + . . . . \infty) = \frac{π}{2}

{sin}^{- 1} (a - \frac{a^{2}}{3} + \frac{a^{3}}{9} \dots \infty) + {cos}^{- 1} (1 + b + b^{2} + b^{3} + \dots \infty) = \frac{π}{2}

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