The correct option is A 8a^2 (2a+1 ) ( 2a 1 ) #160; 32a^4 8a^2 =8a^2(4a^2 1) =8a^2((2a)^2 1^2) =8a^2(2a+1)(2a 1) #160; #16 ...

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Expansion of (x^2 - y^2)

Factorize 3...

Question

Factorize
$32 a^{4} - 8 a^{2}$

8 a^{2} (2 a + 1) (2 a - 1)

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8 a^{2} (2 a^{2} - 1) (2 a - 1)

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a^{2} (2 a + 1) (2 a^{2} - 1)

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a^{2} (2 a - 1) (2 a - 1)

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Solution

The correct option is A $8 a^{2} (2 a + 1) (2 a - 1)$
$32 a^{4} - 8 a^{2}$
$= 8 a^{2} (4 a^{2} - 1)$
$= 8 a^{2} ((2 a)^{2} - 1^{2})$
$= 8 a^{2} (2 a + 1) (2 a - 1)$ .................. $(a^{2} - b^{2}) = (a + b) (a - b)$

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