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Question

Factorize each of the following algebraic expression:
a2 + 3a − 88

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Solution

To factorise a2+3a-88, we will find two numbers p and q such that p+q=3 and pq=-88.Now, 11+(-8)=3 and 11×(-8)=-88Splitting the middle term 3a in the given quadratic as 11a-8a, we get:a2+3a-88=a2+11a-8a-88 =(a2+11a)-(8a+88) =a(a+11)-8(a+11) =(a-8)(a+11)

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