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Question

Factorize each of the following algebraic expression:
a2 + 4ab + 3b2

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Solution

a2+4ab+3b2=a2+4ab+4b2-b2=[a2+2×a×2b+(2b)2]-b2=(a+2b)2-b2=[(a+2b)-b][(a+2b)+b]=(a+2b-b)(a+2b+b)=(a+b)(a+3b)

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