Factorize each of the following algebraic expression:
x2+2x+1−9y2
Given expression x2+2x+1−9y2
Here x2+2x+1 is in the form of a2+2ab+b2=(a+b)2
So, x2+2x(1)+(1)2=(x+1)2
Thus, the expression can be written as
x2+2x+1−9y2=(x+1)2−9y2
⇒x2+2x+1−9y2=(x+1)2−(3y)2
Again from the formula of a2−b2=(a+b)(a−b)
⇒x2+2x+1−9y2=[(x+1)+(3y)][(x+1)−(3y)]
Therefore, the factorized form of the given expression is (x+3y+1)(x−3y+1)