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Question

Factorize each of the following algebraic expression:
x2+2x+19y2

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Solution

Given expression x2+2x+19y2
Here x2+2x+1 is in the form of a2+2ab+b2=(a+b)2
So, x2+2x(1)+(1)2=(x+1)2
Thus, the expression can be written as
x2+2x+19y2=(x+1)29y2
x2+2x+19y2=(x+1)2(3y)2
Again from the formula of a2b2=(a+b)(ab)
x2+2x+19y2=[(x+1)+(3y)][(x+1)(3y)]
Therefore, the factorized form of the given expression is (x+3y+1)(x3y+1)


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