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Question

Factorize each of the following expression:
(3x + 4y)4 − x4

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Solution

(3x+4y)4-x4=[(3x+4y)2]2-(x2)2=[(3x+4y)2+x2][(3x+4y)2-x2]=[(3x+4y)2+x2][(3x+4y)+x][(3x+4y)-x]={(3x+4y)2+x2}(3x+4y+x)(3x+4y-x)=3x+4y2+x2(4x+4y)(2x+4y)=3x+4y2+x24(x+y)2(x+2y)=83x+4y2+x2(x+y)(x+2y)

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