Question

Factorize : $\frac{1}{2}{a}^2-8b^2$

• A. $\frac{1}{2}(a+4b)(a-4b)$
• B. $\frac{1}{2}(a+16b)(a-16b)$
• C. $\frac{1}{2}(a+8b)(a-8b)$
• D. $\frac{1}{2}(a-4b)(a-4b)$

Answer 1

The correct option is A $\frac{1}{2}(a+4b)(a-4b)$

$\frac{1}{2}{a}^2-32b^2$ = $\frac{1}{2}(a^2-16b^2)$

$\frac{1}{2}(a^2-16b^2)$ = $\frac{1}{2}(a+4b)(a-4b)$

Ans: $\frac{1}{2}(a+4b)(a-4b)$