Factorize:
$m^{2} - 4 m - 21$

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Solution

We need to factorise $m^{2} - 4 m - 21$
It can be written as $m^{2} - 4 m - 21 = m^{2} - 7 m + 3 m - 21$
$= m (m - 7) + 3 (m - 7)$
$= (m - 7) (m + 3)$

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Similar questions

m^{2} - 4 m - 21

Find the third side of a triangle whose two sides are $(3 m^{2} - 5 m$ ) and $(4 m^{2} + 12$ ) and perimeter is $(8 m^{2} - 9 m + 4$ ).

Find the third side of a triangle whose perimeter is $8 m^{2} - 9 m + 4$ and two of its sides are $3 m^{2} - 5 m$ and $4 m^{2} + 12$ .

\frac{m^{2} + 3 m}{m^{2} + 4 m + 3} \times \frac{m^{2} - 2 m - 3}{m^{2} - 9}

Factorize: $m^{4} - 256.$

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