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Question

Factorize the below equation:
6a2a15

A
(a)(a+3)
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B
(a5)(2a+5)
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C
(3a5)(2a+3)
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D
(a5)(a3)
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Solution

The correct option is A (3a5)(2a+3)
6a2a15
6a210a+9a+15
2a(3a5)+3(3a5)
(3a5)(2a+3)

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