Factorize the below equation:
$a^{2} b^{2} + 8 a b - 9$

(a + b) (b - 1)

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(b + 9) (a + b)

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(a b + 9) (a b - 1)

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(b + 9) (a - b)

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Solution

The correct option is C $(a b + 9) (a b - 1)$
$a^{2} b^{2} + 8 a b - 9$
$= a^{2} b^{2} + 9 a b - a b - 9$
$= a b (a b + 9) - (a b + 9)$
$= (a b + 9) (a b - 1)$

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