Factorize the equation $3 a^{5} - 108 a^{3}$

3 a^{8} (6) (a - 6)

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3 a^{3} (a + 6) (a - 6)

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3 a^{5} (a + 6) (a + 6)

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3 a^{2} (6) (a - 6)

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Solution

The correct option is B $3 a^{3} (a + 6) (a - 6)$
$3 a^{5} - 108 a^{3}$
$= 3 a^{3} (a^{2} - 36)$
$= 3 a^{3} (a^{2} - 6^{2})$
Using,
$a^{2} - b^{2} = (a + b) (a - b)$
$= 3 a^{3} (a + 6) (a - 6)$

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A

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