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Question

Factorize the equation 4a2−12a+9−49b2

A
(2a7b3)(a7b3)
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B
(2a+b3)(2a11b3)
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C
(2a+b+3)(2a5b3)
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D
(2a+7b3)(2a7b3)
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Solution

The correct option is A (2a+7b3)(2a7b3)
4a212a+949b2
=(2a)22(2a)(3)+(3)2(7b)2
=(2a3)2(7b)2
=(2a3+7b)(2a37b)

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