Question

Factorize the following:
28a² + 14a²b² − 21a⁴

Answer 1

$$\begin{gathered} Thegreatestcommonfactoroftheterms28a^2,14a^2{b}^{2}and21a^{4}oftheexpression28a^2+14a^2{b}^2-21a^{4}is7a^2. \\ Also,wecanwrite28a^2=7a^2\times 4,14a^2{b}^2=7a^2\times 2b^{2}and21a^4=7a^2\times 3a^2. \\ \therefore 28a^2+14a^2{b}^2-21a^4=7a^2\times 4+7a^2\times 2b^2-7a^2\times 3a^2 \\ =7a^2(4+2b^2-3a^2) \end{gathered}$$