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Question

Factorize the following
5y2−29y+20

A
(5y4)(y5)
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B
(5y+4)(y5)
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C
(5y4)(y+5)
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D
None of these
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Solution

The correct option is A (5y4)(y5)
Given
5y229y+20

254=29 .............the split of the middle term

25×4=100...........the split of the last term

Now, splitting we get

=5y225y4y+20
=5y(y5)4(y5)

=(y5)(5y4)

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