Question

Factorize the following algebraic expression:

$96-4x-x^2$

Answer 1

Given: $96-4x-x^2$

$=-x^2-4x+96$

$=-x^2-12x+8x+96$

$=-x(x+12)+8(x+12)$

$=(x+12)(-x+8)$

$=(x+12)(8-x)$

$\therefore 96-4x-x^2=(x+12)(8-x)$