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Question

Factorize the following equation by the grouping method
16(a+b)24a4b

A
(a+b)(3a+4b7)
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B
4(ab)(a+4b1)
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C
4(a+b)(a+b1)
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D
4(a+b)(4a+4b1)
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Solution

The correct option is D 4(a+b)(4a+4b1)
16(a+b)24a4b
=16(a+b)24(a+b)
=4(a+b)(4a+4b1)

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