Question

Factorize the following equation by the grouping method

$16{(a+b)}^2-4a-4b$

• A. $(a+b)(3a+4b-7)$
• B. $4(a-b)(a+4b-1)$
• C. $4(a+b)(a+b-1)$
• D. $4(a+b)(4a+4b-1)$

Answer 1

The correct option is D $4(a+b)(4a+4b-1)$

$16{(a+b)}^2-4a-4b$
$=16{(a+b)}^2-4(a+b)$
$=4(a+b)(4a+4b-1)$