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Question

Factorize the following equation by the grouping method
a3+a−3a2−3

A
(a2+3)(a9)
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B
(a2+1)(a3)
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C
(a3+1)(3a)
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D
(a4+1)(7a)
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Solution

The correct option is A (a2+1)(a3)
a3+a3a23
=a(a2+1)3(a2+1)
=(a2+1)(a3)

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