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Question

Factorize the following equation by the grouping method
m(x−3y)2+n(3y−x)+5x−15y

A
(x3y)(mxmyn5)
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B
(xy)(x3myn5)
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C
(x3y)(mx3myn+5)
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D
(xy)(x3myn+5)
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Solution

The correct option is D (x3y)(mx3myn+5)
m(x3y)2+n(3yx)+5x15y
=m(x3y)2n(3y+x)+5(x3y)
=(x3y)[m(x3y)n+5]
=(x3y)(mx3myn+5)

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