Factorize the following
$y^{2} - y - 20$

(y + 4) (y - 5)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(y - 4) (y - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(y + 4) (y + 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(y + 4) (y - 5)$
$y^{2} - y - 20$

Using

$- 5 + 4 = - 1$ ...........the middle term coefficient splitting

$- 5 \times 4 = - 20$ ..........the last term
$y^{2} - 5 y + 4 y - 20$

Now, splitting the middle term we get

$y (y - 5) + 4 (y - 5)$

$= (y - 5) (y + 4)$

Suggest Corrections

Similar questions

Factorize:

$12 (x + y)^{2} - (x + y) - 35$

Q. If

a_{1}

and

a_{2}

are the zeros of the quadratic polynomial

p (y) = y^{2} - y - 2

then find the polynomial whose zeros are

2 a_{1} + 1

and and

2 a_{2} + 1

Simplify the following:

$(i) (1.5 x - 4 y) (1.5 x + 4 y + 3)$

$(i i) (x + y) (2 x + y) + (x + 2 y) (x - y)$

$(i i i) (a^{2} + 5) (b^{3} + 3) + 5$ [3 MARKS]

Q. The equation of the line which is perpendicular to

x + 4 y - 5 = 0

at it's

y

intercept

Q. Rational expression

\frac{y^{3} - 8}{y^{2} - 4}

written in its lowest form is .

Join BYJU'S Learning Program

Factorize the followingy2−y−20

The correct option is C (y+4)(y−5)y2−y−20 Using−5+4=−1...........the middle term coefficient splitting −5×4=−20..........the last term y2−5y+4y−20 Now, splitting the middle term we gety(y−5)+4(y−5) =(y−5)(y+4)

Factorize the following
$y^{2} - y - 20$

The correct option is C $(y + 4) (y - 5)$
$y^{2} - y - 20$

Using

$- 5 + 4 = - 1$ ...........the middle term coefficient splitting

$- 5 \times 4 = - 20$ ..........the last term
$y^{2} - 5 y + 4 y - 20$

Now, splitting the middle term we get

$y (y - 5) + 4 (y - 5)$

$= (y - 5) (y + 4)$