Factorize:

$y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x$

Open in App

Solution

$\Rightarrow y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x$

$\Rightarrow (y^{3} - 3 y^{2}) + (2 y - 6) - (x y - 3 x)$

$\Rightarrow y^{2} (y - 3) + 2 (y - 3) - x (y - 3)$

$\Rightarrow (y - 3) (y^{2} + 2 - x)$

$\Rightarrow - (3 - y) (y^{2} + 2 - x)$

$\Rightarrow (3 - y) (x - 2 - y^{2})$

Suggest Corrections

Similar questions

y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x

Factorise:

(i) ; (ii) ; (iii) ;

(iv)

Factorize:

$y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x$

(3 x + 2 y + x y + 6)

(y + 3)

3 x + 2 y = 12

x y = 6

9 x^{2} + 4 y^{2}

Join BYJU'S Learning Program