Factors - 5x-1x2 - 5 5x- 1x-6

Let (5x 1x)=k So, k^2+5k+6=k^2+3k+2k+6=k(k+3)+2(k+3)=(k+2)(k+3) =(5x 1x+2)(5x 1x+3) ...

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Factorisation by Common Factors

Factors : 5...

Question

Factors : ${(5 x - \frac{1}{x})}^{2} + 5 (5 x - \frac{1}{x}) + 6$

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Similar questions

Now in each of the pairs of polynomials given below, check whether the first is a factor of the second:

(i) x + 1, x³ − 1

(ii) x − 1, x³ + 1

(iii) x + 1, x³ + 1

(iv) x² − 1, x⁴ − 1

(v) x − 1, x⁴ − 1

(vi) x + 1, x⁴ − 1

(vii) x − 2, x² − 5x + 1

(viii) x + 2, x² + 5x + 6

(ix)

(x) 1.3x − 2.6, x² − 5x + 6

:

x^{2} + 5 x + 6 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 5 x - 6 = 0

x^{2} - 5 x - 6 = 0

According to factor theorem, x-6 is the factor of $x^{2} - 5 x - 6$

(x^{2} + \frac{x}{6} - \frac{1}{6})

\frac{(5 x - 6 + x^{2})}{(x - 1)}

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