Factors of $12 - x - x^{2}$ are:

(x + 2) (x - 3)

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(x + 4) (3 - x)

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(x - 2) (x - 3)

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None of these

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Solution

The correct option is B $(x + 4) (3 - x)$
$12 - x - x^{2} = - (x^{2} + x - 12)$
$= - (x^{2} + 4 x - 3 x - 12)$
$= - [x (x + 4) - 3 (x + 4)]$
$= - [(x + 4) (x - 3)]$
$= (x + 4) (3 - x)$

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If $y = [\frac{x^{2} + 1}{x + 1}], t h e n \frac{d y}{d x}$ =?

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