If y-x2-1-x-1- then d y-d x-x2-2 x-1-x-12B- -x2-2 x-1-x-123 x2-2 x-1-x-12D- none of these

The correct option is A Here u(x) = x^2 + 2x, v(x) = 3x 4 Using quotient rule, dy/dx = (3x 4)d(x^2+2x)/dx (x^2+2x)d(3x 4)/dx/(3x 4)^2 = (3x 4)(2x+2) (x^2+2 ...

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Byju's Answer

Standard XII

Physics

Basic Differentiation Rule

If y=[x2+1/x+...

Question

If $y = [\frac{x^{2} + 1}{x + 1}], t h e n \frac{d y}{d x}$ =?

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none of these

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Solution

The correct option is A

$H e r e u (x) = x^{2} + 2 x, v (x) = 3 x - 4 U s i n g q u o t i e n t r u l e, \frac{d y}{d x} = \frac{(3 x - 4) \frac{d (x^{2} + 2 x)}{d x} - (x^{2} + 2 x) \frac{d (3 x - 4)}{d x}}{(3 x - 4)^{2}} = \frac{(3 x - 4) (2 x + 2) - (x^{2} + 2 x) 3}{(3 x - 4)^{2}} = \frac{3 x^{2} - 8 x - 8}{(3 x - 4)^{2}}$

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Similar questions

If $y = [\frac{x^{2} + 2 x}{3 x - 4}], t h e n \frac{d y}{d x}$ =?

If $y = s i n^{- 1} (x \sqrt{1 - x} + \sqrt{x} \sqrt{1 - x^{2}})$ then $\frac{d y}{d x} =$

Q. If

y = log {⎡ ⎢ ⎢ ⎣ \frac{\sqrt{(1 + x) + \sqrt{(1 - x)}}}{\sqrt{(1 + x) - \sqrt{(1 - x)}}} ⎤ ⎥ ⎥ ⎦}^{1 / 2}

then show that

\frac{d y}{d x} = \frac{1}{2 x \sqrt{(1 - x^{2})}}

Q. Find

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y = {sin}^{- 1} (2 x \sqrt{1 - x^{2}})

\frac{- 1}{\sqrt{2}} < x < \frac{1}{\sqrt{2}}

Q. If

I = \int \frac{d x}{1 + \sqrt{x^{2} + 2 x + 2}} = \frac{A}{7} log ∣ ∣ x + 1 + \sqrt{x^{2} + 2 x + 2} ∣ ∣ - \frac{\sqrt{x^{2} + 2 x + 2} - 1}{x + 1} + C

then A is equal to

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If y=[x2+1x+1], then dydx=?

The correct option is A Here u(x)=x2+2x,v(x)=3x−4Using quotient rule,dydx=(3x−4)d(x2+2x)dx−(x2+2x)d(3x−4)dx(3x−4)2=(3x−4)(2x+2)−(x2+2x)3(3x−4)2=3x2−8x−8(3x−4)2

If $y = [\frac{x^{2} + 1}{x + 1}], t h e n \frac{d y}{d x}$ =?