Factors of $(27 y^{3} - 125 z^{3})$ are

(3 y + 5 z) (9 y^{2} + 25 z^{2} - 15 y z)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(3 y - 5 z) (9 y^{2} + 25 z^{2} + 15 y z)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(3 y + 5 z) (9 y^{2} - 25 z^{2} + 15 y z)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(3 y - 5 z) (9 y^{2} - 25 z^{2} - 15 y z)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(3 y + 5 z) (9 y^{2} + 25 z^{2} - 15 y z)$
$27 y^{3} + 125 z^{3}$
$= {(3 y)}^{3} + {(5 z)}^{3}$
$= (3 y + 5 z) [{(3 y)}^{2} + {(5 z)}^{2} - 3 y \times 5 z]$
$(3 y + 5 z) (9 y^{2} + 25 z^{2} - 15 y z)$
$[∵ a^{3} + b^{3} = (a + b) (a^{2} + b^{2} - a b)]$

Suggest Corrections

Similar questions

(x - 3 y - 5 z) (x^{2} + 9 y^{2} + 25 z^{2} + 3 x y - 15 y z + 5 z x)

(2 x - 3 y + 5 z)

(4 x^{2} + 9 y^{2} + 25 z^{2} + 6 x y + 15 y z - 10 x z)

4 x^{2} + 9 y^{2} + 25 z^{2} - 12 x y - 30 y z + 20 z x

2 x \times (- 15 y z) \times 3 x z

Factorise :

$(3 x - 4 y)^{2} - 25 z^{2}$

Join BYJU'S Learning Program