CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factors of

x3125


A

(x+5)(x25x+25)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

1(x+5)(x25x+25)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

(x5)(x2+5x25)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

1(x5)(x25x+25)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

1(x+5)(x25x+25)


x3125

Take 1 common from the expression, we get

1(x3+125)

=1(x3+53)

=1(x+5)(x25x+25)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon