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Preparation of Alkyl Halides

Fastest rate ...

Question

Fastest rate of reaction will be when $R$ is:

C H_{3} -

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C H_{3} - C H_{2}

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C H_{3} - C | H C H_{3} -

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C H_{3} - C H_{3} | C | H C H_{3} -

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Solution

The correct option is A $C H_{3} -$
Rate of reaction will be fast if the $R$ group is less hindered i.e., less sterically hindered. As in option A, we have three hydrogen atoms attached to the carbon atom as the hydrogen atoms are small, so no bulkiness is experienced by the group, the reaction's rate will be groups in comparison groups given in other options.
so (A) is right option.

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S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

C H_{3} - C H | C H_{3} - C H_{2} - C H | C H_{3} - C H | C H_{3} - C H_{3}

C H_{3} - C H | C H_{3} - C H | C H_{3} - C H_{3}

I U P A C

A g N O_{3}

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

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