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Byju's Answer
Standard XII
Chemistry
Heat of Reaction
Fe 2 O 3 +3CO...
Question
F
e
2
O
3
+
3
C
O
→
2
F
e
+
3
C
O
2
F
e
O
+
C
O
→
F
e
+
C
O
2
△
r
H
=
−
26
k
J
△
r
H
=
−
16
k
J
Find
△
H
of reaction
F
e
2
O
3
+
C
O
→
2
F
e
O
+
C
O
2
△
r
H
=
?
Open in App
Solution
Given:-
F
e
2
C
O
3
+
3
C
O
⟶
2
F
e
+
3
C
O
2
Δ
H
r
=
−
26
k
J
.
.
.
.
.
(
1
)
F
e
O
+
C
O
⟶
F
e
+
C
O
2
Δ
H
=
−
16
k
J
F
e
+
C
O
2
⟶
C
O
+
F
e
O
Δ
H
=
16
k
J
2
×
[
F
e
+
C
O
2
⟶
C
O
+
F
e
O
Δ
H
=
16
k
J
]
2
F
e
+
2
C
O
2
⟶
2
C
O
+
2
F
e
O
Δ
H
=
32
k
J
.
.
.
.
.
(
2
)
Adding
e
q
n
(
1
)
&
(
2
)
, we have
F
e
2
C
O
3
+
3
C
O
+
2
F
e
+
2
C
O
2
⟶
2
F
e
+
3
C
O
2
+
2
C
O
+
2
F
e
O
Δ
H
=
(
−
26
)
+
(
32
)
k
J
F
e
2
C
O
3
+
C
O
⟶
2
F
e
O
+
C
O
2
Δ
H
=
6
k
J
Hence
Δ
H
for the given reaction is
6
k
J
.
Suggest Corrections
1
Similar questions
Q.
F
e
2
O
3
+
2
A
l
→
A
l
2
O
3
+
2
F
e
The above reaction is an example of a :
Q.
Calculate, the
Δ
H
at
85
o
C
for the reaction:
F
e
2
O
3
(
s
)
+
3
H
2
⟶
2
F
e
(
s
)
+
3
H
2
O
(
l
)
The data are:
Δ
H
o
298
=
−
33.29
k
J
/
m
o
l
and
Substance
F
e
2
O
3
(
s
)
F
e
(
s
)
H
2
O
(
l
)
H
2
(
g
)
C
o
P
(
J
/
K
m
o
l
)
103.8
25.1
75.3
28.8
Q.
Given that:
2
F
e
(
s
)
+
3
2
O
2
(
g
)
⟶
F
e
2
O
3
(
s
)
;
Δ
H
=
−
193.4
k
J
.
.
.
(
i
)
M
g
(
s
)
+
1
2
O
2
(
g
)
⟶
M
g
O
(
s
)
;
Δ
H
=
−
140.2
k
J
.
.
.
.
(
i
i
)
What is
Δ
H
of the reaction?
3
M
g
+
F
e
2
O
3
⟶
3
M
g
O
+
2
F
e
Q.
For the reaction
F
e
2
O
3
+
3
C
O
⟶
2
F
e
+
3
C
O
2
the volume of carbon monoxide required to reduce one mole of ferric oxide is:
Q.
Determine the heat of the following reaction:
F
e
O
(
s
)
+
F
e
2
O
3
(
s
)
⟶
F
e
3
O
4
(
s
)
Given informations:
2
F
e
(
s
)
+
O
2
(
g
)
⟶
2
F
e
O
(
s
)
;
Δ
H
o
=
−
544
k
J
4
F
e
(
s
)
+
3
O
2
(
g
)
⟶
2
F
e
2
O
;
3
(
s
)
;
Δ
H
o
=
−
1648.4
k
J
F
e
3
O
4
(
s
)
⟶
3
F
e
(
s
)
+
2
O
2
(
g
)
;
Δ
H
o
=
+
1118.4
k
J
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