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Question

Fe2O3+3CO2Fe+3CO2FeO+COFe+CO2rH=26kJrH=16kJ
Find H of reaction
Fe2O3+CO2FeO+CO2rH=?

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Solution

Given:-
Fe2CO3+3CO2Fe+3CO2ΔHr=26kJ.....(1)
FeO+COFe+CO2ΔH=16kJ
Fe+CO2CO+FeOΔH=16kJ
2×[Fe+CO2CO+FeOΔH=16kJ]
2Fe+2CO22CO+2FeOΔH=32kJ.....(2)
Adding eqn(1)&(2), we have
Fe2CO3+3CO+2Fe+2CO22Fe+3CO2+2CO+2FeOΔH=(26)+(32)kJ
Fe2CO3+CO2FeO+CO2ΔH=6kJ
Hence ΔHfor the given reaction is 6kJ.

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