Question

$\left[Fe\right(H_{2}O{)}_{5}NO{]}^{2+}$ has $O.N.$ of $Fe$ as +1 and thus magnetic moment of $Fe$ is $\sqrt{15}B.M.$. If true enter 1 else 0.

Answer 1

The correct answer is1

The complex $\left[Fe\right(H_{2}O{)}_{5}NO{]}^{2+}$ has 3 unpaired electrons.

$\mu =\sqrt{n(n+2)}$

$=\sqrt{3(3+2)}$

$=\sqrt{15}B.M.$.