Question

Fig represents an area $A=0.5m^2$ situated in a uniform magnetic field $B=2.0weber/m^2$ and making an angle of ${60}^o$ with respect to magnetic flux through the area would be equal to

• A. $2.0$ weber
• B. $\sqrt{3}$ weber
• C. $\sqrt{3}/2$ weber
• D. $0.5$ weber

Answer 1

The correct option is D $0.5$ weber

$\varphi =BA\cos \theta$

$=2.0\times 0.5\times \cos {60}^o$

$=\frac{2.0\times 0.5}{2}=0.5$ Weber.