Question

Fig. shows a brick of weight $2kgf$ and dimensions $20cm\times 10\times cm\times 5cm$ placed in three different positions on the ground. Find the pressure exerted by the brick in each case.

Answer 1

We know that $P=\frac{F}{A}$, here A=effective area

In first case , $P=\frac{mg}{A}=\frac{2\times 10}{0.1\times 0.2}=1000Pa$

In second case , $P=\frac{2\times 10}{0.05\times 0.1}=4000Pa$

In third case , $P=\frac{2\times 10}{0.05\times 0.2}=2000Pa$